3[2(x+1)-4]=10-5(4-2x)

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Solution for 3[2(x+1)-4]=10-5(4-2x) equation:


Simplifying
3[2(x + 1) + -4] = 10 + -5(4 + -2x)

Reorder the terms:
3[2(1 + x) + -4] = 10 + -5(4 + -2x)
3[(1 * 2 + x * 2) + -4] = 10 + -5(4 + -2x)
3[(2 + 2x) + -4] = 10 + -5(4 + -2x)

Reorder the terms:
3[2 + -4 + 2x] = 10 + -5(4 + -2x)

Combine like terms: 2 + -4 = -2
3[-2 + 2x] = 10 + -5(4 + -2x)
[-2 * 3 + 2x * 3] = 10 + -5(4 + -2x)
[-6 + 6x] = 10 + -5(4 + -2x)
-6 + 6x = 10 + (4 * -5 + -2x * -5)
-6 + 6x = 10 + (-20 + 10x)

Combine like terms: 10 + -20 = -10
-6 + 6x = -10 + 10x

Solving
-6 + 6x = -10 + 10x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-10x' to each side of the equation.
-6 + 6x + -10x = -10 + 10x + -10x

Combine like terms: 6x + -10x = -4x
-6 + -4x = -10 + 10x + -10x

Combine like terms: 10x + -10x = 0
-6 + -4x = -10 + 0
-6 + -4x = -10

Add '6' to each side of the equation.
-6 + 6 + -4x = -10 + 6

Combine like terms: -6 + 6 = 0
0 + -4x = -10 + 6
-4x = -10 + 6

Combine like terms: -10 + 6 = -4
-4x = -4

Divide each side by '-4'.
x = 1

Simplifying
x = 1

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